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2013112302020 = 225291734506553
BaseRepresentation
bin11101010010110110110…
…101111111100111000100
321010110012020221210211122
4131102312311333213010
5230440323222131040
64140451103053112
7265304541142601
oct35226665774704
97113166853748
102013112302020
1170683545a426
122861a32a1198
13117ab2c96171
146d6140cd6a8
15375742141b5
hex1d4b6d7f9c4

2013112302020 has 24 divisors (see below), whose sum is σ = 4228985232024. Its totient is φ = 804968845056.

The previous prime is 2013112302017. The next prime is 2013112302029. The reversal of 2013112302020 is 202032113102.

It can be written as a sum of positive squares in 4 ways, for example, as 1298911531204 + 714200770816 = 1139698^2 + 845104^2 .

It is a super-2 number, since 2×20131123020202 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2013112302020.

It is not an unprimeable number, because it can be changed into a prime (2013112302029) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17194937 + ... + 17311616.

It is an arithmetic number, because the mean of its divisors is an integer number (176207718001).

Almost surely, 22013112302020 is an apocalyptic number.

2013112302020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

2013112302020 is an abundant number, since it is smaller than the sum of its proper divisors (2215872930004).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013112302020 is a wasteful number, since it uses less digits than its factorization.

2013112302020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34509479 (or 34509477 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2013112302020 its reverse (202032113102), we get a palindrome (2215144415122).

It can be divided in two parts, 2013112 and 302020, that added together give a palindrome (2315132).

The spelling of 2013112302020 in words is "two trillion, thirteen billion, one hundred twelve million, three hundred two thousand, twenty".

Divisors: 1 2 4 5 10 20 2917 5834 11668 14585 29170 58340 34506553 69013106 138026212 172532765 345065530 690131060 100655615101 201311230202 402622460404 503278075505 1006556151010 2013112302020