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20131300231020 = 22335119661350803
BaseRepresentation
bin1001001001111001011101…
…11111111100011101101100
32122021112101221000022221000
410210330232333330131230
510114312400324343040
6110452105221440300
74145303246411136
oct444745677743554
978245357008830
1020131300231020
116461700181a60
1223116b7870090
13b304b1674724
144d85082a8056
1524d9dbe33130
hex124f2effc76c

20131300231020 has 192 divisors, whose sum is σ = 68331679879680. Its totient is φ = 4879796140800.

The previous prime is 20131300231013. The next prime is 20131300231061. The reversal of 20131300231020 is 2013200313102.

20131300231020 is a `hidden beast` number, since 2 + 0 + 1 + 31 + 300 + 2 + 310 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 20131300230984 and 20131300231002.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 57210939 + ... + 57561741.

It is an arithmetic number, because the mean of its divisors is an integer number (355894166040).

Almost surely, 220131300231020 is an apocalyptic number.

20131300231020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20131300231020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (34165839939840).

20131300231020 is an abundant number, since it is smaller than the sum of its proper divisors (48200379648660).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20131300231020 is a wasteful number, since it uses less digits than its factorization.

20131300231020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 360493 (or 360485 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 20131300231020 its reverse (2013200313102), we get a palindrome (22144500544122).

The spelling of 20131300231020 in words is "twenty trillion, one hundred thirty-one billion, three hundred million, two hundred thirty-one thousand, twenty".