Base | Representation |
---|---|
bin | 10010101111111010… |
… | …110100111010111111 |
3 | 1220221222121011020122 |
4 | 102233322310322333 |
5 | 312212103144403 |
6 | 13125335405155 |
7 | 1311605152532 |
oct | 225772647277 |
9 | 56858534218 |
10 | 20131303103 |
11 | 85a0660a8a |
12 | 3a99b237bb |
13 | 1b8a95b592 |
14 | d8d904a19 |
15 | 7cc555838 |
hex | 4afeb4ebf |
20131303103 has 2 divisors, whose sum is σ = 20131303104. Its totient is φ = 20131303102.
The previous prime is 20131303099. The next prime is 20131303121. The reversal of 20131303103 is 30130313102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20131303103 - 22 = 20131303099 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20131309103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065651551 + 10065651552.
It is an arithmetic number, because the mean of its divisors is an integer number (10065651552).
Almost surely, 220131303103 is an apocalyptic number.
20131303103 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131303103 is an equidigital number, since it uses as much as digits as its factorization.
20131303103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 20131303103 its reverse (30130313102), we get a palindrome (50261616205).
Subtracting 20131303103 from its reverse (30130313102), we obtain a palindrome (9999009999).
The spelling of 20131303103 in words is "twenty billion, one hundred thirty-one million, three hundred three thousand, one hundred three".
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