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2013132099949 is a prime number
BaseRepresentation
bin11101010010111000000…
…001100001000101101101
321010110020122012122111021
4131102320001201011231
5230440343304144244
64140453051254141
7265305201340525
oct35227001410555
97113218178437
102013132099949
11706845651953
122861a9a4a351
13117ab7108609
146d6169a4685
1537575d25284
hex1d4b806116d

2013132099949 has 2 divisors, whose sum is σ = 2013132099950. Its totient is φ = 2013132099948.

The previous prime is 2013132099899. The next prime is 2013132099989. The reversal of 2013132099949 is 9499902313102.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1097057234025 + 916074865924 = 1047405^2 + 957118^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013132099949 - 239 = 1463376286061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2013132099896 and 2013132099905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013132099989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006566049974 + 1006566049975.

It is an arithmetic number, because the mean of its divisors is an integer number (1006566049975).

Almost surely, 22013132099949 is an apocalyptic number.

It is an amenable number.

2013132099949 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013132099949 is an equidigital number, since it uses as much as digits as its factorization.

2013132099949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 944784, while the sum is 52.

The spelling of 2013132099949 in words is "two trillion, thirteen billion, one hundred thirty-two million, ninety-nine thousand, nine hundred forty-nine".