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2013141123263 is a prime number
BaseRepresentation
bin11101010010111000100…
…011111100000010111111
321010110021021012002011002
4131102320203330002333
5230440403111421023
64140454012520515
7265305341131544
oct35227043740277
97113237162132
102013141123263
1170684a755236
122861b0a8013b
13117ab8c4775a
146d617c72bcb
1537576a08b28
hex1d4b88fc0bf

2013141123263 has 2 divisors, whose sum is σ = 2013141123264. Its totient is φ = 2013141123262.

The previous prime is 2013141123197. The next prime is 2013141123289. The reversal of 2013141123263 is 3623211413102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2013141123263 - 212 = 2013141119167 is a prime.

It is a super-2 number, since 2×20131411232632 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013141123293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006570561631 + 1006570561632.

It is an arithmetic number, because the mean of its divisors is an integer number (1006570561632).

Almost surely, 22013141123263 is an apocalyptic number.

2013141123263 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013141123263 is an equidigital number, since it uses as much as digits as its factorization.

2013141123263 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 2013141123263 its reverse (3623211413102), we get a palindrome (5636352536365).

The spelling of 2013141123263 in words is "two trillion, thirteen billion, one hundred forty-one million, one hundred twenty-three thousand, two hundred sixty-three".