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2013141124411 = 5034002268637
BaseRepresentation
bin11101010010111000100…
…011111100010100111011
321010110021021012010201121
4131102320203330110323
5230440403111440121
64140454012530111
7265305341135104
oct35227043742473
97113237163647
102013141124411
1170684a75608a
122861b0a80937
13117ab8c48131
146d617c733ab
1537576a09141
hex1d4b88fc53b

2013141124411 has 4 divisors (see below), whose sum is σ = 2017143393552. Its totient is φ = 2009138855272.

The previous prime is 2013141124403. The next prime is 2013141124429. The reversal of 2013141124411 is 1144211413102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013141124411 - 23 = 2013141124403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013141124811) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2001133816 + ... + 2001134821.

It is an arithmetic number, because the mean of its divisors is an integer number (504285848388).

Almost surely, 22013141124411 is an apocalyptic number.

2013141124411 is a deficient number, since it is larger than the sum of its proper divisors (4002269141).

2013141124411 is an equidigital number, since it uses as much as digits as its factorization.

2013141124411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4002269140.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 2013141124411 its reverse (1144211413102), we get a palindrome (3157352537513).

The spelling of 2013141124411 in words is "two trillion, thirteen billion, one hundred forty-one million, one hundred twenty-four thousand, four hundred eleven".

Divisors: 1 503 4002268637 2013141124411