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201315201401050 = 252112171272121357
BaseRepresentation
bin101101110001100001011001…
…000100010100000011011010
3222101210112201112002200210021
4231301201121010110003122
5202341322013024313200
61552054532103541054
760255354234626542
oct5561413104240332
9871715645080707
10201315201401050
115916632aa07100
121a6b429975a78a
138843c3285a289
14379d9ca05c322
151841a0c80d41a
hexb718591140da

201315201401050 has 216 divisors, whose sum is σ = 439254188049852. Its totient is φ = 68356242662400.

The previous prime is 201315201400991. The next prime is 201315201401053. The reversal of 201315201401050 is 50104102513102.

It can be written as a sum of positive squares in 6 ways, for example, as 122695786236969 + 78619415164081 = 11076813^2 + 8866759^2 .

It is a super-2 number, since 2×2013152014010502 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (201315201401053) by changing a digit.

It is a polite number, since it can be written in 107 ways as a sum of consecutive naturals, for example, 1658806972 + ... + 1658928328.

Almost surely, 2201315201401050 is an apocalyptic number.

201315201401050 is an abundant number, since it is smaller than the sum of its proper divisors (237938986648802).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201315201401050 is a wasteful number, since it uses less digits than its factorization.

201315201401050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121662 (or 121519 counting only the distinct ones).

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 201315201401050 its reverse (50104102513102), we get a palindrome (251419303914152).

The spelling of 201315201401050 in words is "two hundred one trillion, three hundred fifteen billion, two hundred one million, four hundred one thousand, fifty".