Base | Representation |
---|---|
bin | 101101110001100101111101… |
… | …001111010100001001100111 |
3 | 222101211000101010202111212112 |
4 | 231301211331033110021213 |
5 | 202341412032411411403 |
6 | 1552101102331111235 |
7 | 60255616555536302 |
oct | 5561457517241147 |
9 | 871730333674775 |
10 | 201320103232103 |
11 | 59168415963349 |
12 | 1a6b52272a251b |
13 | 884453426691b |
14 | 379dd33087b39 |
15 | 1841be7d229d8 |
hex | b7197d3d4267 |
201320103232103 has 4 divisors (see below), whose sum is σ = 201323418459120. Its totient is φ = 201316788005088.
The previous prime is 201320103232097. The next prime is 201320103232121. The reversal of 201320103232103 is 301232301023102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 201320103232103 - 218 = 201320102969959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201320103237103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1657522418 + ... + 1657643871.
It is an arithmetic number, because the mean of its divisors is an integer number (50330854614780).
Almost surely, 2201320103232103 is an apocalyptic number.
201320103232103 is a deficient number, since it is larger than the sum of its proper divisors (3315227017).
201320103232103 is an equidigital number, since it uses as much as digits as its factorization.
201320103232103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3315227016.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 201320103232103 its reverse (301232301023102), we get a palindrome (502552404255205).
The spelling of 201320103232103 in words is "two hundred one trillion, three hundred twenty billion, one hundred three million, two hundred thirty-two thousand, one hundred three".
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