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20132061471 = 3213731629203
BaseRepresentation
bin10010101111111101…
…101110000100011111
31220222001000200112100
4102233331232010133
5312212301431341
613125403540143
71311614461524
oct225775560437
956861020470
1020132061471
1185a1029835
123a9a22a653
131b8ab65812
14d8da6114b
157cc6553b6
hex4aff6e11f

20132061471 has 12 divisors (see below), whose sum is σ = 29100841848. Its totient is φ = 13411590864.

The previous prime is 20132061427. The next prime is 20132061539. The reversal of 20132061471 is 17416023102.

20132061471 is a `hidden beast` number, since 2 + 0 + 132 + 0 + 61 + 471 = 666.

It is not a de Polignac number, because 20132061471 - 29 = 20132060959 is a prime.

It is a super-3 number, since 3×201320614713 (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20132061071) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 802245 + ... + 826958.

It is an arithmetic number, because the mean of its divisors is an integer number (2425070154).

Almost surely, 220132061471 is an apocalyptic number.

20132061471 is a deficient number, since it is larger than the sum of its proper divisors (8968780377).

20132061471 is a wasteful number, since it uses less digits than its factorization.

20132061471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1630582 (or 1630579 counting only the distinct ones).

The product of its (nonzero) digits is 2016, while the sum is 27.

Adding to 20132061471 its reverse (17416023102), we get a palindrome (37548084573).

The spelling of 20132061471 in words is "twenty billion, one hundred thirty-two million, sixty-one thousand, four hundred seventy-one".

Divisors: 1 3 9 1373 4119 12357 1629203 4887609 14662827 2236895719 6710687157 20132061471