Base | Representation |
---|---|
bin | 10010101111111101… |
… | …101110000100011111 |
3 | 1220222001000200112100 |
4 | 102233331232010133 |
5 | 312212301431341 |
6 | 13125403540143 |
7 | 1311614461524 |
oct | 225775560437 |
9 | 56861020470 |
10 | 20132061471 |
11 | 85a1029835 |
12 | 3a9a22a653 |
13 | 1b8ab65812 |
14 | d8da6114b |
15 | 7cc6553b6 |
hex | 4aff6e11f |
20132061471 has 12 divisors (see below), whose sum is σ = 29100841848. Its totient is φ = 13411590864.
The previous prime is 20132061427. The next prime is 20132061539. The reversal of 20132061471 is 17416023102.
20132061471 is a `hidden beast` number, since 2 + 0 + 132 + 0 + 61 + 471 = 666.
It is not a de Polignac number, because 20132061471 - 29 = 20132060959 is a prime.
It is a super-3 number, since 3×201320614713 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20132061071) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 802245 + ... + 826958.
It is an arithmetic number, because the mean of its divisors is an integer number (2425070154).
Almost surely, 220132061471 is an apocalyptic number.
20132061471 is a deficient number, since it is larger than the sum of its proper divisors (8968780377).
20132061471 is a wasteful number, since it uses less digits than its factorization.
20132061471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1630582 (or 1630579 counting only the distinct ones).
The product of its (nonzero) digits is 2016, while the sum is 27.
Adding to 20132061471 its reverse (17416023102), we get a palindrome (37548084573).
The spelling of 20132061471 in words is "twenty billion, one hundred thirty-two million, sixty-one thousand, four hundred seventy-one".
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