Base | Representation |
---|---|
bin | 101101110001100110111010… |
… | …100000011100100011000111 |
3 | 222101211010000202221021222211 |
4 | 231301212322200130203013 |
5 | 202341421134032230002 |
6 | 1552101352330404251 |
7 | 60255654206544265 |
oct | 5561467240344307 |
9 | 871733022837884 |
10 | 201321131133127 |
11 | 591688a3103625 |
12 | 1a6b5473590687 |
13 | 88446691c2595 |
14 | 379ddcd7b9435 |
15 | 1841c581b5dd7 |
hex | b719ba81c8c7 |
201321131133127 has 2 divisors, whose sum is σ = 201321131133128. Its totient is φ = 201321131133126.
The previous prime is 201321131133061. The next prime is 201321131133167. The reversal of 201321131133127 is 721331131123102.
It is a happy number.
201321131133127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201321131133127 - 27 = 201321131132999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201321131133167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100660565566563 + 100660565566564.
It is an arithmetic number, because the mean of its divisors is an integer number (100660565566564).
Almost surely, 2201321131133127 is an apocalyptic number.
201321131133127 is a deficient number, since it is larger than the sum of its proper divisors (1).
201321131133127 is an equidigital number, since it uses as much as digits as its factorization.
201321131133127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 31.
Adding to 201321131133127 its reverse (721331131123102), we get a palindrome (922652262256229).
The spelling of 201321131133127 in words is "two hundred one trillion, three hundred twenty-one billion, one hundred thirty-one million, one hundred thirty-three thousand, one hundred twenty-seven".
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