201321210113 has 2 divisors, whose sum is σ = 201321210114. Its totient is φ = 201321210112.

The previous prime is 201321210109. The next prime is 201321210131. The reversal of 201321210113 is 311012123102.

Together with next prime (201321210131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 201083186929 + 238023184 = 448423^2 + 15428^2 .

It is a cyclic number.

It is not a de Polignac number, because 201321210113 - 2² = 201321210109 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 201321210091 and 201321210100.

It is not a weakly prime, because it can be changed into another prime (201321210313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100660605056 + 100660605057.

It is an arithmetic number, because the mean of its divisors is an integer number (100660605057).

Almost surely, 2^201321210113 is an apocalyptic number.

It is an amenable number.

201321210113 is a deficient number, since it is larger than the sum of its proper divisors (1).

201321210113 is an equidigital number, since it uses as much as digits as its factorization.

201321210113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 201321210113 its reverse (311012123102), we get a palindrome (512333333215).

The spelling of 201321210113 in words is "two hundred one billion, three hundred twenty-one million, two hundred ten thousand, one hundred thirteen".