Base | Representation |
---|---|
bin | 1001001001111011000001… |
… | …00101101100101000010111 |
3 | 2122021121112220112022012121 |
4 | 10210331200211230220113 |
5 | 10114321101321224343 |
6 | 110452323542000411 |
7 | 4145333001211324 |
oct | 444754045545027 |
9 | 78247486468177 |
10 | 20132132211223 |
11 | 6461a97875aaa |
12 | 23118aa416107 |
13 | b305b4b439c6 |
14 | 4d8586999b4b |
15 | 24da39ec5aed |
hex | 124f6096ca17 |
20132132211223 has 2 divisors, whose sum is σ = 20132132211224. Its totient is φ = 20132132211222.
The previous prime is 20132132211221. The next prime is 20132132211241. The reversal of 20132132211223 is 32211223123102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20132132211223 - 21 = 20132132211221 is a prime.
Together with 20132132211221, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20132132211221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066066105611 + 10066066105612.
It is an arithmetic number, because the mean of its divisors is an integer number (10066066105612).
Almost surely, 220132132211223 is an apocalyptic number.
20132132211223 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132132211223 is an equidigital number, since it uses as much as digits as its factorization.
20132132211223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 20132132211223 its reverse (32211223123102), we get a palindrome (52343355334325).
The spelling of 20132132211223 in words is "twenty trillion, one hundred thirty-two billion, one hundred thirty-two million, two hundred eleven thousand, two hundred twenty-three".
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