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2013214015 = 5433929891
BaseRepresentation
bin111011111111111…
…0011010100111111
312012022012212110001
41313333303110333
513110340322030
6531434055131
7100614015421
oct16777632477
95168185401
102013214015
1194345253a
1248227a4a7
13261122ac7
14151538811
15bbb22cca
hex77ff353f

2013214015 has 8 divisors (see below), whose sum is σ = 2421438768. Its totient is φ = 1606849920.

The previous prime is 2013214009. The next prime is 2013214031. The reversal of 2013214015 is 5104123102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2013214015 - 213 = 2013205823 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2013213983 and 2013214001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 462781 + ... + 467110.

It is an arithmetic number, because the mean of its divisors is an integer number (302679846).

Almost surely, 22013214015 is an apocalyptic number.

2013214015 is a deficient number, since it is larger than the sum of its proper divisors (408224753).

2013214015 is an equidigital number, since it uses as much as digits as its factorization.

2013214015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 930329.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 2013214015 is about 44868.8535066364. The cubic root of 2013214015 is about 1262.6897305288.

Adding to 2013214015 its reverse (5104123102), we get a palindrome (7117337117).

The spelling of 2013214015 in words is "two billion, thirteen million, two hundred fourteen thousand, fifteen".

Divisors: 1 5 433 2165 929891 4649455 402642803 2013214015