20132211121333 has 2 divisors, whose sum is σ = 20132211121334. Its totient is φ = 20132211121332.

The previous prime is 20132211121331. The next prime is 20132211121433. The reversal of 20132211121333 is 33312111223102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15741706926724 + 4390504194609 = 3967582^2 + 2095353^2 .

It is a cyclic number.

It is not a de Polignac number, because 20132211121333 - 2¹ = 20132211121331 is a prime.

It is a super-3 number, since 3×20132211121333³ (a number of 41 digits) contains 333 as substring.

Together with 20132211121331, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 20132211121298 and 20132211121307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20132211121331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066105560666 + 10066105560667.

It is an arithmetic number, because the mean of its divisors is an integer number (10066105560667).

Almost surely, 2^{20132211121333} is an apocalyptic number.

It is an amenable number.

20132211121333 is a deficient number, since it is larger than the sum of its proper divisors (1).

20132211121333 is an equidigital number, since it uses as much as digits as its factorization.

20132211121333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 20132211121333 its reverse (33312111223102), we get a palindrome (53444322344435).

The spelling of 20132211121333 in words is "twenty trillion, one hundred thirty-two billion, two hundred eleven million, one hundred twenty-one thousand, three hundred thirty-three".