Base | Representation |
---|---|
bin | 1001001001111011011011… |
… | …00100111001001000100101 |
3 | 2122021122010002112102001012 |
4 | 10210331231210321020211 |
5 | 10114322023111312401 |
6 | 110452401324112005 |
7 | 4145341255240454 |
oct | 444755544711045 |
9 | 78248102472035 |
10 | 20132350104101 |
11 | 646209986a164 |
12 | 231194b395605 |
13 | b3061b0242c1 |
14 | 4d85a78b8b9b |
15 | 24da4e1b68bb |
hex | 124f6d939225 |
20132350104101 has 2 divisors, whose sum is σ = 20132350104102. Its totient is φ = 20132350104100.
The previous prime is 20132350104059. The next prime is 20132350104107. The reversal of 20132350104101 is 10140105323102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20071699221025 + 60650883076 = 4480145^2 + 246274^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132350104101 - 230 = 20131276362277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20132350104107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066175052050 + 10066175052051.
It is an arithmetic number, because the mean of its divisors is an integer number (10066175052051).
Almost surely, 220132350104101 is an apocalyptic number.
It is an amenable number.
20132350104101 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132350104101 is an equidigital number, since it uses as much as digits as its factorization.
20132350104101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 20132350104101 its reverse (10140105323102), we get a palindrome (30272455427203).
The spelling of 20132350104101 in words is "twenty trillion, one hundred thirty-two billion, three hundred fifty million, one hundred four thousand, one hundred one".
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