Base | Representation |
---|---|
bin | 10010101111111111… |
… | …000001000010010101 |
3 | 1220222001122221200122 |
4 | 102233333001002111 |
5 | 312212343320201 |
6 | 13125415121325 |
7 | 1311620405345 |
oct | 225777010225 |
9 | 56861587618 |
10 | 20132401301 |
11 | 85a1241091 |
12 | 3a9a373245 |
13 | 1b8ac543bc |
14 | d8db0cd25 |
15 | 7cc6c0e1b |
hex | 4affc1095 |
20132401301 has 2 divisors, whose sum is σ = 20132401302. Its totient is φ = 20132401300.
The previous prime is 20132401169. The next prime is 20132401309. The reversal of 20132401301 is 10310423102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19196102500 + 936298801 = 138550^2 + 30599^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20132401301 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20132401301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20132401309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066200650 + 10066200651.
It is an arithmetic number, because the mean of its divisors is an integer number (10066200651).
Almost surely, 220132401301 is an apocalyptic number.
It is an amenable number.
20132401301 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132401301 is an equidigital number, since it uses as much as digits as its factorization.
20132401301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 20132401301 its reverse (10310423102), we get a palindrome (30442824403).
The spelling of 20132401301 in words is "twenty billion, one hundred thirty-two million, four hundred one thousand, three hundred one".
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