Base | Representation |
---|---|
bin | 1001001001111011100010… |
… | …10010100111000011010001 |
3 | 2122021122021102210101210202 |
4 | 10210331301102213003101 |
5 | 10114322140034422210 |
6 | 110452411431504545 |
7 | 4145342643022403 |
oct | 444756122470321 |
9 | 78248242711722 |
10 | 20132412420305 |
11 | 6462120a62259 |
12 | 2311968228155 |
13 | b3062ac025b3 |
14 | 4d85b1c9ab73 |
15 | 24da548c59a5 |
hex | 124f714a70d1 |
20132412420305 has 8 divisors (see below), whose sum is σ = 24158938653312. Its totient is φ = 16105900770288.
The previous prime is 20132412420259. The next prime is 20132412420313. The reversal of 20132412420305 is 50302421423102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20132412420305 - 218 = 20132412158161 is a prime.
It is a super-2 number, since 2×201324124203052 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 335279 + ... + 6354308.
It is an arithmetic number, because the mean of its divisors is an integer number (3019867331664).
Almost surely, 220132412420305 is an apocalyptic number.
It is an amenable number.
20132412420305 is a deficient number, since it is larger than the sum of its proper divisors (4026526233007).
20132412420305 is an equidigital number, since it uses as much as digits as its factorization.
20132412420305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7291495.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 20132412420305 its reverse (50302421423102), we get a palindrome (70434833843407).
The spelling of 20132412420305 in words is "twenty trillion, one hundred thirty-two billion, four hundred twelve million, four hundred twenty thousand, three hundred five".
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