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20132414353 is a prime number
BaseRepresentation
bin10010101111111111…
…000100001110010001
31220222001200121121001
4102233333010032101
5312212344224403
613125415302001
71311620461402
oct225777041621
956861617531
1020132414353
1185a124a977
123a9a37a901
131b8ac5a31c
14d8db139a9
157cc6c4c1d
hex4affc4391

20132414353 has 2 divisors, whose sum is σ = 20132414354. Its totient is φ = 20132414352.

The previous prime is 20132414321. The next prime is 20132414371. The reversal of 20132414353 is 35341423102.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20065289104 + 67125249 = 141652^2 + 8193^2 .

It is a cyclic number.

It is not a de Polignac number, because 20132414353 - 25 = 20132414321 is a prime.

It is not a weakly prime, because it can be changed into another prime (20132414153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066207176 + 10066207177.

It is an arithmetic number, because the mean of its divisors is an integer number (10066207177).

Almost surely, 220132414353 is an apocalyptic number.

It is an amenable number.

20132414353 is a deficient number, since it is larger than the sum of its proper divisors (1).

20132414353 is an equidigital number, since it uses as much as digits as its factorization.

20132414353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 20132414353 its reverse (35341423102), we get a palindrome (55473837455).

The spelling of 20132414353 in words is "twenty billion, one hundred thirty-two million, four hundred fourteen thousand, three hundred fifty-three".