Base | Representation |
---|---|
bin | 10010101111111111… |
… | …000100001110010001 |
3 | 1220222001200121121001 |
4 | 102233333010032101 |
5 | 312212344224403 |
6 | 13125415302001 |
7 | 1311620461402 |
oct | 225777041621 |
9 | 56861617531 |
10 | 20132414353 |
11 | 85a124a977 |
12 | 3a9a37a901 |
13 | 1b8ac5a31c |
14 | d8db139a9 |
15 | 7cc6c4c1d |
hex | 4affc4391 |
20132414353 has 2 divisors, whose sum is σ = 20132414354. Its totient is φ = 20132414352.
The previous prime is 20132414321. The next prime is 20132414371. The reversal of 20132414353 is 35341423102.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20065289104 + 67125249 = 141652^2 + 8193^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132414353 - 25 = 20132414321 is a prime.
It is not a weakly prime, because it can be changed into another prime (20132414153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066207176 + 10066207177.
It is an arithmetic number, because the mean of its divisors is an integer number (10066207177).
Almost surely, 220132414353 is an apocalyptic number.
It is an amenable number.
20132414353 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132414353 is an equidigital number, since it uses as much as digits as its factorization.
20132414353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 20132414353 its reverse (35341423102), we get a palindrome (55473837455).
The spelling of 20132414353 in words is "twenty billion, one hundred thirty-two million, four hundred fourteen thousand, three hundred fifty-three".
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