Base | Representation |
---|---|
bin | 10010101111111111… |
… | …000100001110100011 |
3 | 1220222001200121121201 |
4 | 102233333010032203 |
5 | 312212344224441 |
6 | 13125415302031 |
7 | 1311620461426 |
oct | 225777041643 |
9 | 56861617551 |
10 | 20132414371 |
11 | 85a124a993 |
12 | 3a9a37a917 |
13 | 1b8ac5a334 |
14 | d8db139bd |
15 | 7cc6c4c31 |
hex | 4affc43a3 |
20132414371 has 2 divisors, whose sum is σ = 20132414372. Its totient is φ = 20132414370.
The previous prime is 20132414353. The next prime is 20132414389. The reversal of 20132414371 is 17341423102.
It is a balanced prime because it is at equal distance from previous prime (20132414353) and next prime (20132414389).
It is a cyclic number.
It is not a de Polignac number, because 20132414371 - 211 = 20132412323 is a prime.
It is not a weakly prime, because it can be changed into another prime (20132414321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066207185 + 10066207186.
It is an arithmetic number, because the mean of its divisors is an integer number (10066207186).
Almost surely, 220132414371 is an apocalyptic number.
20132414371 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132414371 is an equidigital number, since it uses as much as digits as its factorization.
20132414371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 20132414371 its reverse (17341423102), we get a palindrome (37473837473).
The spelling of 20132414371 in words is "twenty billion, one hundred thirty-two million, four hundred fourteen thousand, three hundred seventy-one".
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