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201325354031 is a prime number
BaseRepresentation
bin1011101101111111101…
…1010001110000101111
3201020122201011122102202
42323133323101300233
511244303242312111
6232253153012115
720355013162634
oct2733773216057
9636581148382
10201325354031
1178421a0630a
123302755403b
1315ca5a93529
149a5c12218b
1553849c1b3b
hex2edfed1c2f

201325354031 has 2 divisors, whose sum is σ = 201325354032. Its totient is φ = 201325354030.

The previous prime is 201325354019. The next prime is 201325354063. The reversal of 201325354031 is 130453523102.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201325354031 - 230 = 200251612207 is a prime.

It is a super-2 number, since 2×2013253540312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201325353985 and 201325354003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201325354631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100662677015 + 100662677016.

It is an arithmetic number, because the mean of its divisors is an integer number (100662677016).

Almost surely, 2201325354031 is an apocalyptic number.

201325354031 is a deficient number, since it is larger than the sum of its proper divisors (1).

201325354031 is an equidigital number, since it uses as much as digits as its factorization.

201325354031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 201325354031 its reverse (130453523102), we get a palindrome (331778877133).

The spelling of 201325354031 in words is "two hundred one billion, three hundred twenty-five million, three hundred fifty-four thousand, thirty-one".