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2013302147 is a prime number
BaseRepresentation
bin111100000000000…
…1000110110000011
312012022101100100012
41320000020312003
513110401132042
6531440015135
7100614533363
oct17000106603
95168340305
102013302147
1194350277a
124823014ab
13261153c5c
1415155c9a3
15bbb3de82
hex78008d83

2013302147 has 2 divisors, whose sum is σ = 2013302148. Its totient is φ = 2013302146.

The previous prime is 2013302131. The next prime is 2013302227. The reversal of 2013302147 is 7412033102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2013302147 - 24 = 2013302131 is a prime.

It is a super-2 number, since 2×20133021472 = 8106771070229619218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2013304147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006651073 + 1006651074.

It is an arithmetic number, because the mean of its divisors is an integer number (1006651074).

Almost surely, 22013302147 is an apocalyptic number.

2013302147 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013302147 is an equidigital number, since it uses as much as digits as its factorization.

2013302147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 23.

The square root of 2013302147 is about 44869.8356025515. The cubic root of 2013302147 is about 1262.7081557511.

Adding to 2013302147 its reverse (7412033102), we get a palindrome (9425335249).

The spelling of 2013302147 in words is "two billion, thirteen million, three hundred two thousand, one hundred forty-seven".