Base | Representation |
---|---|
bin | 11101010011000010101… |
… | …000001100001010011011 |
3 | 21010110201000222102012211 |
4 | 131103002220030022123 |
5 | 230441224330310021 |
6 | 4140522444415551 |
7 | 265312461502666 |
oct | 35230250141233 |
9 | 7113630872184 |
10 | 2013310010011 |
11 | 706927017363 |
12 | 2862395475b7 |
13 | 117b14c2a141 |
14 | 6d6324766dd |
15 | 375867693e1 |
hex | 1d4c2a0c29b |
2013310010011 has 2 divisors, whose sum is σ = 2013310010012. Its totient is φ = 2013310010010.
The previous prime is 2013310009999. The next prime is 2013310010039. The reversal of 2013310010011 is 1100100133102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013310010011 - 219 = 2013309485723 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2013310009973 and 2013310010000.
It is not a weakly prime, because it can be changed into another prime (2013310010051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006655005005 + 1006655005006.
It is an arithmetic number, because the mean of its divisors is an integer number (1006655005006).
Almost surely, 22013310010011 is an apocalyptic number.
2013310010011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013310010011 is an equidigital number, since it uses as much as digits as its factorization.
2013310010011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 2013310010011 its reverse (1100100133102), we get a palindrome (3113410143113).
The spelling of 2013310010011 in words is "two trillion, thirteen billion, three hundred ten million, ten thousand, eleven".
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