Base | Representation |
---|---|
bin | 11101010011000010101… |
… | …000001100001010110111 |
3 | 21010110201000222102020212 |
4 | 131103002220030022313 |
5 | 230441224330310124 |
6 | 4140522444420035 |
7 | 265312461503036 |
oct | 35230250141267 |
9 | 7113630872225 |
10 | 2013310010039 |
11 | 706927017389 |
12 | 28623954761b |
13 | 117b14c2a163 |
14 | 6d63247671d |
15 | 3758676940e |
hex | 1d4c2a0c2b7 |
2013310010039 has 2 divisors, whose sum is σ = 2013310010040. Its totient is φ = 2013310010038.
The previous prime is 2013310010011. The next prime is 2013310010051. The reversal of 2013310010039 is 9300100133102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013310010039 - 212 = 2013310005943 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2013310009996 and 2013310010023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013310010069) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006655005019 + 1006655005020.
It is an arithmetic number, because the mean of its divisors is an integer number (1006655005020).
Almost surely, 22013310010039 is an apocalyptic number.
2013310010039 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013310010039 is an equidigital number, since it uses as much as digits as its factorization.
2013310010039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 23.
The spelling of 2013310010039 in words is "two trillion, thirteen billion, three hundred ten million, ten thousand, thirty-nine".
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