2013312031333 has 4 divisors (see below), whose sum is σ = 2060133241408. Its totient is φ = 1966490821260.

The previous prime is 2013312031331. The next prime is 2013312031343. The reversal of 2013312031333 is 3331302133102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013312031333 - 2¹ = 2013312031331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2013312031298 and 2013312031307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013312031331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23410604973 + ... + 23410605058.

It is an arithmetic number, because the mean of its divisors is an integer number (515033310352).

Almost surely, 2^{2013312031333} is an apocalyptic number.

It is an amenable number.

2013312031333 is a deficient number, since it is larger than the sum of its proper divisors (46821210075).

2013312031333 is an equidigital number, since it uses as much as digits as its factorization.

2013312031333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46821210074.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 2013312031333 its reverse (3331302133102), we get a palindrome (5344614164435).

The spelling of 2013312031333 in words is "two trillion, thirteen billion, three hundred twelve million, thirty-one thousand, three hundred thirty-three".