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2013312043100 = 225220133120431
BaseRepresentation
bin11101010011000010101…
…111111100100001011100
321010110201011210201002102
4131103002233330201130
5230441230340334400
64140523000144232
7265312515001241
oct35230257744134
97113634721072
102013312043100
117069281858a6
1228623a168078
13117b1548c657
146d6328455c8
1537586a1b9d5
hex1d4c2bfc85c

2013312043100 has 18 divisors (see below), whose sum is σ = 4368887133744. Its totient is φ = 805324817200.

The previous prime is 2013312043063. The next prime is 2013312043133. The reversal of 2013312043100 is 13402133102.

It is a super-2 number, since 2×20133120431002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 10066560116 + ... + 10066560315.

Almost surely, 22013312043100 is an apocalyptic number.

2013312043100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

2013312043100 is an abundant number, since it is smaller than the sum of its proper divisors (2355575090644).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013312043100 is a wasteful number, since it uses less digits than its factorization.

2013312043100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20133120445 (or 20133120438 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 2013312043100 its reverse (13402133102), we get a palindrome (2026714176202).

The spelling of 2013312043100 in words is "two trillion, thirteen billion, three hundred twelve million, forty-three thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 20133120431 40266240862 80532481724 100665602155 201331204310 402662408620 503328010775 1006656021550 2013312043100