Base | Representation |
---|---|
bin | 11101010011000010101… |
… | …111111100100001011100 |
3 | 21010110201011210201002102 |
4 | 131103002233330201130 |
5 | 230441230340334400 |
6 | 4140523000144232 |
7 | 265312515001241 |
oct | 35230257744134 |
9 | 7113634721072 |
10 | 2013312043100 |
11 | 7069281858a6 |
12 | 28623a168078 |
13 | 117b1548c657 |
14 | 6d6328455c8 |
15 | 37586a1b9d5 |
hex | 1d4c2bfc85c |
2013312043100 has 18 divisors (see below), whose sum is σ = 4368887133744. Its totient is φ = 805324817200.
The previous prime is 2013312043063. The next prime is 2013312043133. The reversal of 2013312043100 is 13402133102.
It is a super-2 number, since 2×20133120431002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 10066560116 + ... + 10066560315.
Almost surely, 22013312043100 is an apocalyptic number.
2013312043100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2013312043100 is an abundant number, since it is smaller than the sum of its proper divisors (2355575090644).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2013312043100 is a wasteful number, since it uses less digits than its factorization.
2013312043100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20133120445 (or 20133120438 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2013312043100 its reverse (13402133102), we get a palindrome (2026714176202).
The spelling of 2013312043100 in words is "two trillion, thirteen billion, three hundred twelve million, forty-three thousand, one hundred".
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