Base | Representation |
---|---|
bin | 11101010011000010110… |
… | …000101010101010100111 |
3 | 21010110201012011022100112 |
4 | 131103002300222222213 |
5 | 230441230412411403 |
6 | 4140523004203235 |
7 | 265312516416254 |
oct | 35230260525247 |
9 | 7113635138315 |
10 | 2013312232103 |
11 | 7069282a48a7 |
12 | 28623a23951b |
13 | 117b155276a3 |
14 | 6d63289442b |
15 | 37586a579d8 |
hex | 1d4c2c2aaa7 |
2013312232103 has 2 divisors, whose sum is σ = 2013312232104. Its totient is φ = 2013312232102.
The previous prime is 2013312232073. The next prime is 2013312232109. The reversal of 2013312232103 is 3012322133102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013312232103 - 230 = 2012238490279 is a prime.
It is a super-2 number, since 2×20133122321032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013312232109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006656116051 + 1006656116052.
It is an arithmetic number, because the mean of its divisors is an integer number (1006656116052).
Almost surely, 22013312232103 is an apocalyptic number.
2013312232103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013312232103 is an equidigital number, since it uses as much as digits as its factorization.
2013312232103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 2013312232103 its reverse (3012322133102), we get a palindrome (5025634365205).
Subtracting 2013312232103 from its reverse (3012322133102), we obtain a palindrome (999009900999).
The spelling of 2013312232103 in words is "two trillion, thirteen billion, three hundred twelve million, two hundred thirty-two thousand, one hundred three".
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