Base | Representation |
---|---|
bin | 1011101110000001001… |
… | …0000000000110101111 |
3 | 201020200010101021220002 |
4 | 2323200102000012233 |
5 | 11244311303423043 |
6 | 232253524414515 |
7 | 20355114623153 |
oct | 2734022000657 |
9 | 636603337802 |
10 | 201331311023 |
11 | 78425304947 |
12 | 3302954743b |
13 | 15ca709aa8b |
14 | 9a5cc33063 |
15 | 538529bbb8 |
hex | 2ee04801af |
201331311023 has 2 divisors, whose sum is σ = 201331311024. Its totient is φ = 201331311022.
The previous prime is 201331310963. The next prime is 201331311037. The reversal of 201331311023 is 320113133102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201331311023 - 212 = 201331306927 is a prime.
It is a super-2 number, since 2×2013313110232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201331310986 and 201331311004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201331311053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100665655511 + 100665655512.
It is an arithmetic number, because the mean of its divisors is an integer number (100665655512).
Almost surely, 2201331311023 is an apocalyptic number.
201331311023 is a deficient number, since it is larger than the sum of its proper divisors (1).
201331311023 is an equidigital number, since it uses as much as digits as its factorization.
201331311023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 201331311023 its reverse (320113133102), we get a palindrome (521444444125).
The spelling of 201331311023 in words is "two hundred one billion, three hundred thirty-one million, three hundred eleven thousand, twenty-three".
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