Base | Representation |
---|---|
bin | 1011101110000001011… |
… | …0010100010101000001 |
3 | 201020200012111202220011 |
4 | 2323200112110111001 |
5 | 11244312101124213 |
6 | 232254004544521 |
7 | 20355130344553 |
oct | 2734026242501 |
9 | 636605452804 |
10 | 201332442433 |
11 | 78425a079a1 |
12 | 330299b2141 |
13 | 15ca73a5a55 |
14 | 9a5d0494d3 |
15 | 538542203d |
hex | 2ee0594541 |
201332442433 has 8 divisors (see below), whose sum is σ = 213277125600. Its totient is φ = 189399048000.
The previous prime is 201332442407. The next prime is 201332442449. The reversal of 201332442433 is 334244233102.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201332442433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 201332442395 and 201332442404.
It is not an unprimeable number, because it can be changed into a prime (201332442463) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2785443 + ... + 2856808.
It is an arithmetic number, because the mean of its divisors is an integer number (26659640700).
Almost surely, 2201332442433 is an apocalyptic number.
It is an amenable number.
201332442433 is a deficient number, since it is larger than the sum of its proper divisors (11944683167).
201332442433 is a wasteful number, since it uses less digits than its factorization.
201332442433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5644367.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 201332442433 its reverse (334244233102), we get a palindrome (535576675535).
The spelling of 201332442433 in words is "two hundred one billion, three hundred thirty-two million, four hundred forty-two thousand, four hundred thirty-three".
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