Base | Representation |
---|---|
bin | 1001001001111101010000… |
… | …00011011110110100110011 |
3 | 2122021201122110122022102122 |
4 | 10210332220003132310303 |
5 | 10114331030241420311 |
6 | 110453042532304455 |
7 | 4145404500362315 |
oct | 444765003366463 |
9 | 78251573568378 |
10 | 20133331201331 |
11 | 6462552652017 |
12 | 2311b83a7212b |
13 | b307463735ca |
14 | 4d865bd057b5 |
15 | 24daaa3b20db |
hex | 124fa80ded33 |
20133331201331 has 4 divisors (see below), whose sum is σ = 20185087837200. Its totient is φ = 20081574565464.
The previous prime is 20133331201147. The next prime is 20133331201429. The reversal of 20133331201331 is 13310213333102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20133331201331 - 226 = 20133264092467 is a prime.
It is a super-3 number, since 3×201333312013313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 20133331201331.
It is not an unprimeable number, because it can be changed into a prime (20133331201031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25878317351 + ... + 25878318128.
It is an arithmetic number, because the mean of its divisors is an integer number (5046271959300).
Almost surely, 220133331201331 is an apocalyptic number.
20133331201331 is a deficient number, since it is larger than the sum of its proper divisors (51756635869).
20133331201331 is an equidigital number, since it uses as much as digits as its factorization.
20133331201331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51756635868.
The product of its (nonzero) digits is 2916, while the sum is 26.
Adding to 20133331201331 its reverse (13310213333102), we get a palindrome (33443544534433).
The spelling of 20133331201331 in words is "twenty trillion, one hundred thirty-three billion, three hundred thirty-one million, two hundred one thousand, three hundred thirty-one".
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