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20133433157 = 23875366659
BaseRepresentation
bin10010110000000010…
…111100111101000101
31220222010121101010112
4102300002330331011
5312213124330112
613125453202405
71311632233565
oct226002747505
956863541115
1020133433157
1185a1886362
123a9a790405
131b8b225c76
14d8dcdada5
157cc826a22
hex4b00bcf45

20133433157 has 4 divisors (see below), whose sum is σ = 21008799840. Its totient is φ = 19258066476.

The previous prime is 20133433153. The next prime is 20133433171. The reversal of 20133433157 is 75133433102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20133433157 - 22 = 20133433153 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20133433153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437683307 + ... + 437683352.

It is an arithmetic number, because the mean of its divisors is an integer number (5252199960).

Almost surely, 220133433157 is an apocalyptic number.

It is an amenable number.

20133433157 is a deficient number, since it is larger than the sum of its proper divisors (875366683).

20133433157 is an equidigital number, since it uses as much as digits as its factorization.

20133433157 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 875366682.

The product of its (nonzero) digits is 22680, while the sum is 32.

Adding to 20133433157 its reverse (75133433102), we get a palindrome (95266866259).

Subtracting 20133433157 from its reverse (75133433102), we obtain a palindrome (54999999945).

The spelling of 20133433157 in words is "twenty billion, one hundred thirty-three million, four hundred thirty-three thousand, one hundred fifty-seven".

Divisors: 1 23 875366659 20133433157