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2013402001463 is a prime number
BaseRepresentation
bin11101010011001000000…
…111000111000000110111
321010110221110002001202122
4131103020013013000313
5230441421403021323
64140535532230155
7265314656431436
oct35231007070067
97113843061678
102013402001463
11706973a38956
1228626430b35b
13117b2acc8658
146d64078111d
153758e88aec8
hex1d4c81c7037

2013402001463 has 2 divisors, whose sum is σ = 2013402001464. Its totient is φ = 2013402001462.

The previous prime is 2013402001427. The next prime is 2013402001489. The reversal of 2013402001463 is 3641002043102.

It is an a-pointer prime, because the next prime (2013402001489) can be obtained adding 2013402001463 to its sum of digits (26).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2013402001463 - 218 = 2013401739319 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013402001363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006701000731 + 1006701000732.

It is an arithmetic number, because the mean of its divisors is an integer number (1006701000732).

Almost surely, 22013402001463 is an apocalyptic number.

2013402001463 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013402001463 is an equidigital number, since it uses as much as digits as its factorization.

2013402001463 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 2013402001463 its reverse (3641002043102), we get a palindrome (5654404044565).

The spelling of 2013402001463 in words is "two trillion, thirteen billion, four hundred two million, one thousand, four hundred sixty-three".