Base | Representation |
---|---|
bin | 1011101110000011011… |
… | …1000000000011010101 |
3 | 201020200210122001120101 |
4 | 2323200313000003111 |
5 | 11244321244311013 |
6 | 232254512334101 |
7 | 20355263230354 |
oct | 2734067000325 |
9 | 636623561511 |
10 | 201341010133 |
11 | 7842a829a3a |
12 | 33030844331 |
13 | 15ca90b56b3 |
14 | 9a6023999b |
15 | 53860658dd |
hex | 2ee0dc00d5 |
201341010133 has 4 divisors (see below), whose sum is σ = 201372530220. Its totient is φ = 201309490048.
The previous prime is 201341010109. The next prime is 201341010181. The reversal of 201341010133 is 331010143102.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 69874578244 + 131466431889 = 264338^2 + 362583^2 .
It is a cyclic number.
It is not a de Polignac number, because 201341010133 - 221 = 201338912981 is a prime.
It is a super-2 number, since 2×2013410101332 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 201341010133.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201341010193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15750460 + ... + 15763237.
It is an arithmetic number, because the mean of its divisors is an integer number (50343132555).
Almost surely, 2201341010133 is an apocalyptic number.
It is an amenable number.
201341010133 is a deficient number, since it is larger than the sum of its proper divisors (31520087).
201341010133 is an equidigital number, since it uses as much as digits as its factorization.
201341010133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31520086.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 201341010133 its reverse (331010143102), we get a palindrome (532351153235).
The spelling of 201341010133 in words is "two hundred one billion, three hundred forty-one million, ten thousand, one hundred thirty-three".
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