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20134101021 = 36711367007
BaseRepresentation
bin10010110000000101…
…100000000000011101
31220222011212022021020
4102300011200000131
5312213312213041
613125515354353
71311641014656
oct226005400035
956864768236
1020134101021
1185a21a2111
123a9aa529b9
131b8b3cac58
14d9003252d
157cc909866
hex4b016001d

20134101021 has 4 divisors (see below), whose sum is σ = 26845468032. Its totient is φ = 13422734012.

The previous prime is 20134100963. The next prime is 20134101023. The reversal of 20134101021 is 12010143102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20134101021 - 211 = 20134098973 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20134101023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355683501 + ... + 3355683506.

It is an arithmetic number, because the mean of its divisors is an integer number (6711367008).

Almost surely, 220134101021 is an apocalyptic number.

It is an amenable number.

20134101021 is a deficient number, since it is larger than the sum of its proper divisors (6711367011).

20134101021 is an equidigital number, since it uses as much as digits as its factorization.

20134101021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6711367010.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20134101021 its reverse (12010143102), we get a palindrome (32144244123).

The spelling of 20134101021 in words is "twenty billion, one hundred thirty-four million, one hundred one thousand, twenty-one".

Divisors: 1 3 6711367007 20134101021