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20134101401 is a prime number
BaseRepresentation
bin10010110000000101…
…100000000110011001
31220222011212022210022
4102300011200012121
5312213312221101
613125515400225
71311641016041
oct226005400631
956864768708
1020134101401
1185a21a2427
123a9aa53075
131b8b3cb18b
14d90032721
157cc909a1b
hex4b0160199

20134101401 has 2 divisors, whose sum is σ = 20134101402. Its totient is φ = 20134101400.

The previous prime is 20134101391. The next prime is 20134101413. The reversal of 20134101401 is 10410143102.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13433041801 + 6701059600 = 115901^2 + 81860^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20134101401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20134101401.

It is not a weakly prime, because it can be changed into another prime (20134101101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067050700 + 10067050701.

It is an arithmetic number, because the mean of its divisors is an integer number (10067050701).

Almost surely, 220134101401 is an apocalyptic number.

It is an amenable number.

20134101401 is a deficient number, since it is larger than the sum of its proper divisors (1).

20134101401 is an equidigital number, since it uses as much as digits as its factorization.

20134101401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 20134101401 its reverse (10410143102), we get a palindrome (30544244503).

The spelling of 20134101401 in words is "twenty billion, one hundred thirty-four million, one hundred one thousand, four hundred one".