2013410321141 has 4 divisors (see below), whose sum is σ = 2013693787392. Its totient is φ = 2013126854892.

The previous prime is 2013410321093. The next prime is 2013410321159. The reversal of 2013410321141 is 1411230143102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2013410321141 is a prime.

It is a super-2 number, since 2×2013410321141² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013410321171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141722471 + ... + 141736676.

It is an arithmetic number, because the mean of its divisors is an integer number (503423446848).

Almost surely, 2^{2013410321141} is an apocalyptic number.

It is an amenable number.

2013410321141 is a deficient number, since it is larger than the sum of its proper divisors (283466251).

2013410321141 is an equidigital number, since it uses as much as digits as its factorization.

2013410321141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 283466250.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 2013410321141 its reverse (1411230143102), we get a palindrome (3424640464243).

The spelling of 2013410321141 in words is "two trillion, thirteen billion, four hundred ten million, three hundred twenty-one thousand, one hundred forty-one".