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2013411034440 = 233251332545657
BaseRepresentation
bin11101010011001000101…
…001100100010101001000
321010110222002001222200100
4131103020221210111020
5230441431211100230
64140540454005400
7265315126262601
oct35231051442510
97113862058610
102013411034440
11706979048523
12286267346860
13117b2cb3c000
146d641a52da8
1537590572660
hex1d4c8a64548

2013411034440 has 192 divisors, whose sum is σ = 7088639266800. Its totient is φ = 495608675328.

The previous prime is 2013411034433. The next prime is 2013411034471. The reversal of 2013411034440 is 444301143102.

2013411034440 is a `hidden beast` number, since 201 + 3 + 4 + 1 + 10 + 3 + 4 + 440 = 666.

It can be written as a sum of positive squares in 8 ways, for example, as 2930923044 + 2010480111396 = 54138^2 + 1417914^2 .

It is a super-2 number, since 2×20134110344402 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 481909 + ... + 2063748.

Almost surely, 22013411034440 is an apocalyptic number.

2013411034440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2013411034440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3544319633400).

2013411034440 is an abundant number, since it is smaller than the sum of its proper divisors (5075228232360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013411034440 is a wasteful number, since it uses less digits than its factorization.

2013411034440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2545713 (or 2545680 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 2013411034440 its reverse (444301143102), we get a palindrome (2457712177542).

The spelling of 2013411034440 in words is "two trillion, thirteen billion, four hundred eleven million, thirty-four thousand, four hundred forty".