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2013411203 = 3754416519
BaseRepresentation
bin111100000000010…
…0011011110000011
312012022120212221022
41320000203132003
513110413124303
6531442220055
7100615466336
oct17000433603
95168525838
102013411203
11943577701
1248235462b
1326119179b
1415158a61d
15bbb61438
hex78023783

2013411203 has 4 divisors (see below), whose sum is σ = 2067827760. Its totient is φ = 1958994648.

The previous prime is 2013411187. The next prime is 2013411229. The reversal of 2013411203 is 3021143102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013411203 - 24 = 2013411187 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013411293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27208223 + ... + 27208296.

It is an arithmetic number, because the mean of its divisors is an integer number (516956940).

Almost surely, 22013411203 is an apocalyptic number.

2013411203 is a deficient number, since it is larger than the sum of its proper divisors (54416557).

2013411203 is an equidigital number, since it uses as much as digits as its factorization.

2013411203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54416556.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2013411203 is about 44871.0508345860. The cubic root of 2013411203 is about 1262.7309546828.

Adding to 2013411203 its reverse (3021143102), we get a palindrome (5034554305).

The spelling of 2013411203 in words is "two billion, thirteen million, four hundred eleven thousand, two hundred three".

Divisors: 1 37 54416519 2013411203