Base | Representation |
---|---|
bin | 101101110001111011011001… |
… | …010001010101001100101011 |
3 | 222101220012210100211012202201 |
4 | 231301323121101111030223 |
5 | 202342301203224213120 |
6 | 1552115430421241031 |
7 | 60260363155644325 |
oct | 5561733121251453 |
9 | 871805710735681 |
10 | 201343122101035 |
11 | 59177158470272 |
12 | 1a6b9790263177 |
13 | 8846762201425 |
14 | 37a10b8288615 |
15 | 18425e3b0d40a |
hex | b71ed945532b |
201343122101035 has 64 divisors (see below), whose sum is σ = 250544139835392. Its totient is φ = 155254580356096.
The previous prime is 201343122101027. The next prime is 201343122101057. The reversal of 201343122101035 is 530101221343102.
It is not a de Polignac number, because 201343122101035 - 23 = 201343122101027 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 201343122100994 and 201343122101012.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3818569842 + ... + 3818622568.
It is an arithmetic number, because the mean of its divisors is an integer number (3914752184928).
Almost surely, 2201343122101035 is an apocalyptic number.
201343122101035 is a deficient number, since it is larger than the sum of its proper divisors (49201017734357).
201343122101035 is a wasteful number, since it uses less digits than its factorization.
201343122101035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54012.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 201343122101035 its reverse (530101221343102), we get a palindrome (731444343444137).
The spelling of 201343122101035 in words is "two hundred one trillion, three hundred forty-three billion, one hundred twenty-two million, one hundred one thousand, thirty-five".
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