Base | Representation |
---|---|
bin | 11101010011001010100… |
… | …000111001000001000111 |
3 | 21010111001020221011121002 |
4 | 131103022200321001013 |
5 | 230442012213024221 |
6 | 4140543532243515 |
7 | 265315656201551 |
oct | 35231240710107 |
9 | 7114036834532 |
10 | 2013442314311 |
11 | 70699477255a |
12 | 28627591059b |
13 | 117b364716cc |
14 | 6d645c764d1 |
15 | 375931a080b |
hex | 1d4ca839047 |
2013442314311 has 2 divisors, whose sum is σ = 2013442314312. Its totient is φ = 2013442314310.
The previous prime is 2013442314287. The next prime is 2013442314313. The reversal of 2013442314311 is 1134132443102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013442314311 - 234 = 1996262445127 is a prime.
Together with 2013442314313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013442314313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006721157155 + 1006721157156.
It is an arithmetic number, because the mean of its divisors is an integer number (1006721157156).
Almost surely, 22013442314311 is an apocalyptic number.
2013442314311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013442314311 is an equidigital number, since it uses as much as digits as its factorization.
2013442314311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 2013442314311 its reverse (1134132443102), we get a palindrome (3147574757413).
The spelling of 2013442314311 in words is "two trillion, thirteen billion, four hundred forty-two million, three hundred fourteen thousand, three hundred eleven".
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