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20134443011 = 58391344821
BaseRepresentation
bin10010110000000110…
…110011100000000011
31220222012111200101112
4102300012303200003
5312213404134021
613125530553535
71311643641014
oct226006634003
956865450345
1020134443011
1185a2406051
123a9ab988ab
131b8b4ba807
14d900c100b
157cc975d5b
hex4b01b3803

20134443011 has 4 divisors (see below), whose sum is σ = 20134846224. Its totient is φ = 20134039800.

The previous prime is 20134442963. The next prime is 20134443019. The reversal of 20134443011 is 11034443102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20134443011 - 26 = 20134442947 is a prime.

It is a super-2 number, since 2×201344430112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20134443019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114020 + ... + 230801.

It is an arithmetic number, because the mean of its divisors is an integer number (5033711556).

Almost surely, 220134443011 is an apocalyptic number.

20134443011 is a deficient number, since it is larger than the sum of its proper divisors (403213).

20134443011 is an equidigital number, since it uses as much as digits as its factorization.

20134443011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 403212.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 20134443011 its reverse (11034443102), we get a palindrome (31168886113).

Subtracting from 20134443011 its reverse (11034443102), we obtain a palindrome (9099999909).

The spelling of 20134443011 in words is "twenty billion, one hundred thirty-four million, four hundred forty-three thousand, eleven".

Divisors: 1 58391 344821 20134443011