Base | Representation |
---|---|
bin | 11101010011001110000… |
… | …000110001111001100101 |
3 | 21010111012100100222122121 |
4 | 131103032000301321211 |
5 | 230442122224133123 |
6 | 4140553430225541 |
7 | 265320301104622 |
oct | 35231600617145 |
9 | 7114170328577 |
10 | 2013501005413 |
11 | 706a14909aa7 |
12 | 2862914b52b1 |
13 | 117b45680981 |
14 | 6d64d993349 |
15 | 375983e575d |
hex | 1d4ce031e65 |
2013501005413 has 4 divisors (see below), whose sum is σ = 2119474742560. Its totient is φ = 1907527268268.
The previous prime is 2013501005401. The next prime is 2013501005429. The reversal of 2013501005413 is 3145001053102.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013501005413 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013501005513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52986868545 + ... + 52986868582.
It is an arithmetic number, because the mean of its divisors is an integer number (529868685640).
Almost surely, 22013501005413 is an apocalyptic number.
It is an amenable number.
2013501005413 is a deficient number, since it is larger than the sum of its proper divisors (105973737147).
2013501005413 is a wasteful number, since it uses less digits than its factorization.
2013501005413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105973737146.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 2013501005413 its reverse (3145001053102), we get a palindrome (5158502058515).
The spelling of 2013501005413 in words is "two trillion, thirteen billion, five hundred one million, five thousand, four hundred thirteen".
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