Base | Representation |
---|---|
bin | 1001001010000000101000… |
… | …00100111100000011001111 |
3 | 2122021220022202211202201022 |
4 | 10211000110010330003033 |
5 | 10114343233220210021 |
6 | 110453542432504355 |
7 | 4145500425014453 |
oct | 445002404740317 |
9 | 78256282752638 |
10 | 20135143522511 |
11 | 64632a2661816 |
12 | 23123aa9ab0bb |
13 | b309749888c4 |
14 | 4d87908a8663 |
15 | 24db645511ab |
hex | 12501413c0cf |
20135143522511 has 2 divisors, whose sum is σ = 20135143522512. Its totient is φ = 20135143522510.
The previous prime is 20135143522489. The next prime is 20135143522589. The reversal of 20135143522511 is 11522534153102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20135143522511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20135143522811) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067571761255 + 10067571761256.
It is an arithmetic number, because the mean of its divisors is an integer number (10067571761256).
Almost surely, 220135143522511 is an apocalyptic number.
20135143522511 is a deficient number, since it is larger than the sum of its proper divisors (1).
20135143522511 is an equidigital number, since it uses as much as digits as its factorization.
20135143522511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 20135143522511 its reverse (11522534153102), we get a palindrome (31657677675613).
The spelling of 20135143522511 in words is "twenty trillion, one hundred thirty-five billion, one hundred forty-three million, five hundred twenty-two thousand, five hundred eleven".
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