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2014012003 = 2644976147
BaseRepresentation
bin111100000001011…
…0110001001100011
312012100201102002011
41320002312021203
513111041341003
6531503133351
7100623551053
oct17002661143
95170642064
102014012003
11943948033
124825a4257
132613420a3
141516a5563
15bbc2e46d
hex780b6263

2014012003 has 4 divisors (see below), whose sum is σ = 2014114600. Its totient is φ = 2013909408.

The previous prime is 2014011977. The next prime is 2014012069. The reversal of 2014012003 is 3002104102.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3002104102 = 21501052051.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2014012003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2014012073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11625 + ... + 64522.

It is an arithmetic number, because the mean of its divisors is an integer number (503528650).

Almost surely, 22014012003 is an apocalyptic number.

2014012003 is a deficient number, since it is larger than the sum of its proper divisors (102597).

2014012003 is an equidigital number, since it uses as much as digits as its factorization.

2014012003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102596.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 2014012003 is about 44877.7450748141. The cubic root of 2014012003 is about 1262.8565414331.

Adding to 2014012003 its reverse (3002104102), we get a palindrome (5016116105).

The spelling of 2014012003 in words is "two billion, fourteen million, twelve thousand, three".

Divisors: 1 26449 76147 2014012003