201411244231 has 2 divisors, whose sum is σ = 201411244232. Its totient is φ = 201411244230.

The previous prime is 201411244213. The next prime is 201411244249. The reversal of 201411244231 is 132442114102.

Together with previous prime (201411244213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (201411244213) and next prime (201411244249).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-201411244231 is a prime.

It is a super-2 number, since 2×201411244231² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201411244196 and 201411244205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201411241231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100705622115 + 100705622116.

It is an arithmetic number, because the mean of its divisors is an integer number (100705622116).

Almost surely, 2^201411244231 is an apocalyptic number.

201411244231 is a deficient number, since it is larger than the sum of its proper divisors (1).

201411244231 is an equidigital number, since it uses as much as digits as its factorization.

201411244231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 201411244231 its reverse (132442114102), we get a palindrome (333853358333).

The spelling of 201411244231 in words is "two hundred one billion, four hundred eleven million, two hundred forty-four thousand, two hundred thirty-one".