Base | Representation |
---|---|
bin | 10010110000100001… |
… | …001011101011010111 |
3 | 1220222200111222200012 |
4 | 102300201023223113 |
5 | 312222141422113 |
6 | 13130335110435 |
7 | 1312056500501 |
oct | 226041135327 |
9 | 56880458605 |
10 | 20141357783 |
11 | 85a62a9238 |
12 | 3aa137241b |
13 | 1b8ca6bcb1 |
14 | d90da0d71 |
15 | 7cd38eaa8 |
hex | 4b084bad7 |
20141357783 has 2 divisors, whose sum is σ = 20141357784. Its totient is φ = 20141357782.
The previous prime is 20141357779. The next prime is 20141357809. The reversal of 20141357783 is 38775314102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20141357783 - 22 = 20141357779 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20141357783.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20141357723) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10070678891 + 10070678892.
It is an arithmetic number, because the mean of its divisors is an integer number (10070678892).
Almost surely, 220141357783 is an apocalyptic number.
20141357783 is a deficient number, since it is larger than the sum of its proper divisors (1).
20141357783 is an equidigital number, since it uses as much as digits as its factorization.
20141357783 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 141120, while the sum is 41.
The spelling of 20141357783 in words is "twenty billion, one hundred forty-one million, three hundred fifty-seven thousand, seven hundred eighty-three".
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