Search a number
-
+
20142011 = 26717541
BaseRepresentation
bin100110011010…
…1011110111011
31101220022122102
41030311132323
520124021021
61555414015
7333130031
oct114653673
941808572
1020142011
1110407a9a
1268b430b
134232c66
142964551
151b7d00b
hex13357bb

20142011 has 4 divisors (see below), whose sum is σ = 20152224. Its totient is φ = 20131800.

The previous prime is 20142007. The next prime is 20142013. The reversal of 20142011 is 11024102.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 11024102 = 25512051.

It is a cyclic number.

It is not a de Polignac number, because 20142011 - 22 = 20142007 is a prime.

It is a Duffinian number.

It is a plaindrome in base 16.

It is a junction number, because it is equal to n+sod(n) for n = 20141983 and 20142001.

It is not an unprimeable number, because it can be changed into a prime (20142013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100 + ... + 6441.

It is an arithmetic number, because the mean of its divisors is an integer number (5038056).

Almost surely, 220142011 is an apocalyptic number.

20142011 is a deficient number, since it is larger than the sum of its proper divisors (10213).

20142011 is an equidigital number, since it uses as much as digits as its factorization.

20142011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10212.

The product of its (nonzero) digits is 16, while the sum is 11.

The square root of 20142011 is about 4487.9851826850. The cubic root of 20142011 is about 272.0827089522.

Adding to 20142011 its reverse (11024102), we get a palindrome (31166113).

The spelling of 20142011 in words is "twenty million, one hundred forty-two thousand, eleven".

Divisors: 1 2671 7541 20142011