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201422433655 = 5134632992237
BaseRepresentation
bin1011101110010110110…
…1100110110101110111
3201020220110211210122101
42323211231212311313
511300003120334110
6232310541442531
720360302302622
oct2734555466567
9636813753571
10201422433655
1178471792703
1233053b70447
1315cbcc239b1
149a6ad92db9
15538d29b13a
hex2ee5b66d77

201422433655 has 8 divisors (see below), whose sum is σ = 241724954592. Its totient is φ = 161125924128.

The previous prime is 201422433643. The next prime is 201422433677. The reversal of 201422433655 is 556334224102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201422433655 is a prime.

It is a super-3 number, since 3×2014224336553 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1428804 + ... + 1563433.

It is an arithmetic number, because the mean of its divisors is an integer number (30215619324).

Almost surely, 2201422433655 is an apocalyptic number.

201422433655 is a deficient number, since it is larger than the sum of its proper divisors (40302520937).

201422433655 is a wasteful number, since it uses less digits than its factorization.

201422433655 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3005705.

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 201422433655 its reverse (556334224102), we get a palindrome (757756657757).

The spelling of 201422433655 in words is "two hundred one billion, four hundred twenty-two million, four hundred thirty-three thousand, six hundred fifty-five".

Divisors: 1 5 13463 67315 2992237 14961185 40284486731 201422433655