Base | Representation |
---|---|
bin | 101101110011001101010110… |
… | …011011000000001000111101 |
3 | 222102012121221011112021100002 |
4 | 231303031112123000020331 |
5 | 202400221414002243031 |
6 | 1552224102442044045 |
7 | 60266626650251213 |
oct | 5563152633001075 |
9 | 872177834467302 |
10 | 201431121134141 |
11 | 59200505644308 |
12 | 1a71284aaa9625 |
13 | 8851b475cb212 |
14 | 37a5465518cb3 |
15 | 1844a44485ccb |
hex | b733566c023d |
201431121134141 has 2 divisors, whose sum is σ = 201431121134142. Its totient is φ = 201431121134140.
The previous prime is 201431121134063. The next prime is 201431121134219. The reversal of 201431121134141 is 141431121134102.
201431121134141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (201431121134063) and next prime (201431121134219).
It can be written as a sum of positive squares in only one way, i.e., 182872989486916 + 18558131647225 = 13523054^2 + 4307915^2 .
It is a cyclic number.
It is not a de Polignac number, because 201431121134141 - 210 = 201431121133117 is a prime.
It is a super-2 number, since 2×2014311211341412 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201431121154141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100715560567070 + 100715560567071.
It is an arithmetic number, because the mean of its divisors is an integer number (100715560567071).
Almost surely, 2201431121134141 is an apocalyptic number.
It is an amenable number.
201431121134141 is a deficient number, since it is larger than the sum of its proper divisors (1).
201431121134141 is an equidigital number, since it uses as much as digits as its factorization.
201431121134141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 29.
Adding to 201431121134141 its reverse (141431121134102), we get a palindrome (342862242268243).
The spelling of 201431121134141 in words is "two hundred one trillion, four hundred thirty-one billion, one hundred twenty-one million, one hundred thirty-four thousand, one hundred forty-one".
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