Base | Representation |
---|---|
bin | 10010110000101100… |
… | …011100101101000111 |
3 | 1220222220002000212201 |
4 | 102300230130231013 |
5 | 312223420423421 |
6 | 13130522255331 |
7 | 1312123551001 |
oct | 226054345507 |
9 | 56886060781 |
10 | 20144311111 |
11 | 85a7a36101 |
12 | 3aa2357547 |
13 | 1b90564322 |
14 | d9152d371 |
15 | 7cd774b91 |
hex | 4b0b1cb47 |
20144311111 has 2 divisors, whose sum is σ = 20144311112. Its totient is φ = 20144311110.
The previous prime is 20144311087. The next prime is 20144311133. The reversal of 20144311111 is 11111344102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20144311111 - 223 = 20135922503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20145311111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072155555 + 10072155556.
It is an arithmetic number, because the mean of its divisors is an integer number (10072155556).
Almost surely, 220144311111 is an apocalyptic number.
20144311111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20144311111 is an equidigital number, since it uses as much as digits as its factorization.
20144311111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 20144311111 its reverse (11111344102), we get a palindrome (31255655213).
The spelling of 20144311111 in words is "twenty billion, one hundred forty-four million, three hundred eleven thousand, one hundred eleven".
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