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20144411431 is a prime number
BaseRepresentation
bin10010110000101100…
…110101001100100111
31220222220021010111021
4102300230311030213
5312223432131211
613130524352011
71312124446324
oct226054651447
956886233437
1020144411431
1185a7aa4511
123aa23a5607
131b9059aba1
14d91557b4b
157cd794771
hex4b0b35327

20144411431 has 2 divisors, whose sum is σ = 20144411432. Its totient is φ = 20144411430.

The previous prime is 20144411411. The next prime is 20144411437. The reversal of 20144411431 is 13411444102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20144411431 - 219 = 20143887143 is a prime.

It is a super-2 number, since 2×201444114312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20144411396 and 20144411405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20144411437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072205715 + 10072205716.

It is an arithmetic number, because the mean of its divisors is an integer number (10072205716).

Almost surely, 220144411431 is an apocalyptic number.

20144411431 is a deficient number, since it is larger than the sum of its proper divisors (1).

20144411431 is an equidigital number, since it uses as much as digits as its factorization.

20144411431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 20144411431 its reverse (13411444102), we get a palindrome (33555855533).

The spelling of 20144411431 in words is "twenty billion, one hundred forty-four million, four hundred eleven thousand, four hundred thirty-one".